Mole ConceptMedium
Question
Equal masses of oxygen, hydrogen and methane are taken in identical conditions. What is the ratio of the volumes of the gases under identical conditions?
Options
A.16: 1: 8
B.1: 16: 2
C.1: 16: 8
D.2: 16: 1
Solution
$V_{O_{2}}:V_{H_{2}}:V_{CH_{4}} = n_{O_{2}}:n_{H_{2}}:n_{CH_{4}}$
$= \frac{w}{32}:\frac{w}{2}:\frac{w}{16} = 1:16:2$
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