KinematicsHard
Question
A disc is performing pure rolling on a smooth stationary surface with constant angular velocity as shown in figure.
Options
A.At any instant, the acceleration of top most point is 
B.At any instant, for the lower most point of the disc velocity is zero, acceleration is zero.
C.At any instant, for the lower most point of the disc velocity is v, acceleration is .
.D.At any instant, for the lower most point of the disc velocity is zero, acceleration is .
.Solution
As the disc in combined rotation and translation, each point has a tangential velocity and a linear velocity in the forward direction.
From figure
vnet (for lower point) = v - Rω = v - v = 0.
and Acceleration =
+ 0 =(Since linear speed is constant) Hence (D).
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