KinematicsMedium
Question
The relation between time t and distance x is t = ax2 + bx where a and b are constants.
The acceleration is
The acceleration is
Options
A.-2abv2
B.2bv3
C.-2av3
D.2av2
Solution
t = ax2 + bx
by differentiating; V=1/(2ax+b)a= V.dV/dX:
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