KinematicsMedium
Question
The co-ordinate of the particle in x - y plane are given as x = 2 + 2t + t2 and y = 4t + 8t2 : -
Options
A.Along a straight line
B.Uniformly accelerated
C.Along a parabolic path
D.Non-uniformly accelerated
Solution
x = 2 + 2t + 4t2, y = 4t + 8t2
vx =
= 2 + 8t, vy = 
= 4 + 16t
ax = 8 ; ay = 16 ;
= 8î + 16ĵ = constant
y = 2(2t + 4t2) ; y = 2(x - 2) (∵ x = 2 + 2t + 4t2)
vx =
= 2 + 8t, vy = = 4 + 16tax = 8 ; ay = 16 ;
= 8î + 16ĵ = constant y = 2(2t + 4t2) ; y = 2(x - 2) (∵ x = 2 + 2t + 4t2)
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