ThermochemistryMedium

Question

Use the following data to calculate the enthalpy of hydration for caesium iodide and caesium hydroxide, respectively.

Compound Lattice energy (kJ/mol) ΔHSolution (kJ/mol)

CsI +604 +33

CsOH +724 −72

Options

A.−571 kJ/mol and −796 kJ/mol
B.637 kJ/mol and 652 kJ/mol
C.−637 kJ/mol and −652 kJ/mol
D.571 kJ/mol and 796 kJ/mol

Solution

$\Delta_{\text{Lattice}}H + \Delta_{\text{Hydration}}H = \Delta_{\text{solution}}H$

$\text{For }CSl:\Delta_{\text{Hyd}}H = 33 - 604 = - 571\text{ kJ} $$$\text{For }CsOH:\Delta_{\text{Hyd}}H = ( - 72) - 724 = - 796\text{ kJ}$$

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