ElectrochemistryHard
Question
The following data are obtained in an experiment
Solution Conductivity
0.01 M HA 3.8 × 10-5Ω-1cm-1
100 ml of 0.01 M HA + 1 mmol NaOH 80.0 × 10-5Ω-1cm-1
Given : λm∞(Na+) = 50Ω-1 cm2 mol-1, λm∞ (H+) = 350Ω-1 cm2mol-1
Than select the correct statement :
Solution Conductivity
0.01 M HA 3.8 × 10-5Ω-1cm-1
100 ml of 0.01 M HA + 1 mmol NaOH 80.0 × 10-5Ω-1cm-1
Given : λm∞(Na+) = 50Ω-1 cm2 mol-1, λm∞ (H+) = 350Ω-1 cm2mol-1
Than select the correct statement :
Options
A.Λm(NaA) is 80Ω-1 cm2 mol-1
B.Λm(A-) is 30Ω-1 cm2 mol-1
C.Λm(HA) is 3.8Ω-1 cm2 mol-1
D.degree of dissociation of 0.01 M HA is 0.01
More Electrochemistry Questions
Which of the following statements is wrong about galvanic cells ?...Electrode potential will be more for hydrogen electrode at pH (at the same temperature)...Given:H2O2 → O2 + 2H+ + 2e- E- = - 0.69 VH2O2 + 2H+ + 2e- → 2H2O E- = - 1.77 VI- → I2 + 2e-Which of th...The electrochemical equivalents of two substances are E1 and E2. The current that must pass to deposit the same amount a...Zn Amalgam is prepared by electrolysis of aqueous ZnCl2 using Hg cathode (9gm). How much current is to be passed through...