ElectrochemistryHard
Question
The following data are obtained in an experiment
Solution Conductivity
0.01 M HA 3.8 × 10-5Ω-1cm-1
100 ml of 0.01 M HA + 1 mmol NaOH 80.0 × 10-5Ω-1cm-1
Given : λm∞(Na+) = 50Ω-1 cm2 mol-1, λm∞ (H+) = 350Ω-1 cm2mol-1
Than select the correct statement :
Solution Conductivity
0.01 M HA 3.8 × 10-5Ω-1cm-1
100 ml of 0.01 M HA + 1 mmol NaOH 80.0 × 10-5Ω-1cm-1
Given : λm∞(Na+) = 50Ω-1 cm2 mol-1, λm∞ (H+) = 350Ω-1 cm2mol-1
Than select the correct statement :
Options
A.Λm(NaA) is 80Ω-1 cm2 mol-1
B.Λm(A-) is 30Ω-1 cm2 mol-1
C.Λm(HA) is 3.8Ω-1 cm2 mol-1
D.degree of dissociation of 0.01 M HA is 0.01
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