Math miscellaneousHard
Question
If one root of the equation ax2 + bx + c = 0 is square of the other, then the value of b3 + ac2 + a2c is :
Options
A.-3abc
B.2abc
C.3abc
D.-2abc
Solution
Let ′α′ be the one root so
α2 + α = -
& α3 = 
Eliminating : we get
b3 + ac2 + a2c = 3abc
α2 + α = -
& α3 = Eliminating : we get
b3 + ac2 + a2c = 3abc
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