Math miscellaneousHard

Question

There are two urns. Urn A has 3 distinct red balls and urn B has 9 distinct blue balls. From each urn two balls are taken out at random and then transferred to the other. The number of ways in which this can be done is

Options

A.36
B.66
C.108
D.3

Solution

Total number of ways = 3C2 × 9C2
= 3 × = 3 × 36 = 108

Create a free account to view solution

View Solution Free
Topic: Math miscellaneous·Practice all Math miscellaneous questions

More Math miscellaneous Questions

Number of possible values of n such that n! has exactly 20 zeroes at the end is equal to -...Number of divisors of 1024 × (225)2 × (25)7 which are of the form 3k + 1 (where k is a whole number) is equal ...If In = dx, n = 0, 1, 2, ... , then...The number of ways of selecting 15 teams from 15 men and 15 women, such that each team consists of a man and a woman, is...Coefficient of x9 in the expansion of is -...