ThermochemistryHard
Question
The ᐃHfo for CO2(g), CO(g) and H2O(g) are - 395.5, - 110.5 and - 241.8 kJ mol-1 respectively. The standard enthalpy enthaly change (in kJ) for the reaction
CO2(g) + H2(g) → CO(g) + H2O(g) is
CO2(g) + H2(g) → CO(g) + H2O(g) is
Options
A.524.1
B.41.2
C.-262.5
D.-41.2
Solution
ᐃH = ᐃ Hof (products) - ᐃHof(reactants)
= - 110.5 + (-241.8) - (-393.5 + 0) = 41.2kJ
= - 110.5 + (-241.8) - (-393.5 + 0) = 41.2kJ
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