Ionic EquilibriumHard
Question
The pH value of N/10 NaOH is :
Options
A.9
B.10
C.12
D.13
Solution
0.1 N NaOH ⇋ Na+ + OH-
Normality of NaOH = Molarity of NaOH =
[OH-] = 10-1
[H+][OH-] = 10-1
[H+] =
= 10-13
∴ pH = - log 10-13
∴ pH = 13
Normality of NaOH = Molarity of NaOH =
[OH-] = 10-1
[H+][OH-] = 10-1
[H+] =
= 10-13∴ pH = - log 10-13
∴ pH = 13
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