ElectrochemistryHard

Question

The charge required for the reduction of 1 mol of MnO4- to MnO2 is :

Options

A.1F
B.3F
C.5F
D.6F

Solution

MnO4- + 4H+ + 3e → MnO2 + 2H2O
So, 3 F of charge will be required to reduce 1 mole of MnO4-

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