ElectrochemistryEasy
Question
Time required to deposit one millimole of aluminum metal by the passage of 9.65 amperes through aqueous solution of aluminum ion is
Options
A.30 s
B.10 s
C.30,000 s
D.10,000 s
Solution
l3+ + 3e- → Al
1mole requires = 3 × 96500 coulomb
1 millimole (10-3mol)requires
= 3 × 96500 × 10-3C
we know that, Q = i t
or t =
=
30 sec.
1mole requires = 3 × 96500 coulomb
1 millimole (10-3mol)requires
= 3 × 96500 × 10-3C
we know that, Q = i t
or t =
=
30 sec.Create a free account to view solution
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