ElectrochemistryEasy

Question

For reducing one mole of Cr₂O₇^2- to Cr³⁺ the cahrge required is :

Options

A.3 × 96500 coulomb

B.6 × 96500 coulomb

C.0.3 Faradays

D.0.6 Faradays

Solution

Cr₂O₇²⁺ + 14 H⁺ + 6e^- → 2Cr³⁺ + 7H₂O
For reducing one mole of Cr₂O₇^2- charge required = 6 × 96500 coulomb.

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