Mole ConceptHard
Question
At 373 K and 1 atm, if the density of liquid water is 1.0 g/ml and that of water vapour is 0.0006 g/ml, then the volume occupied by water molecules in 1 litre of steam at that temperature is
Options
A.6 ml
B.60 ml
C.0.6 ml
D.0.06 ml
Solution
Mass of water molecules in 1 litre of steam = 0.0006 × 1000 = 0.6 g. As for H2O system, the most condensed state is liquid water, we may assume that in liquid water, the intermolecular space is negligible in comparison to the volume occupied by the liquid molecule. Hence, the volume occupied by the water molecules =$\frac{0.6}{1.0}$= 0.6 mL.
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