Atomic StructureHard
Question
A photon of energy 4 eV is incident on a metal surface whose work function is 2eV. The minimum reverse potential to be applied for stopping the emission of the electrons is
Options
A.2V
B.4V
C.6V
D.8V
Solution
From Einstein′s equation of photoelectric effect
hv = φ +
mv2
hv = φ + Ve [V is stoping potential]
4eV = 2eV + Ve
Ve = 2e volt
V × e = 2 × e × 1volt
V(Stoping potential) = 2Volt
hv = φ +
mv2 hv = φ + Ve [V is stoping potential]
4eV = 2eV + Ve
Ve = 2e volt
V × e = 2 × e × 1volt
V(Stoping potential) = 2Volt
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
During a nuclear fusion reaction...If the binding energy of the electron in a hydrogen atom is 13.6 eV, the energy required to remove the electron from the...Three concentric metal shells A, B and C of respective radii a, b and c (a < b < c) have surface charge densities ...The electron in the hydrogen atom jumps from excited state (n = 3) to its ground state (n = 1) and the photons thus emit...Radioactive nuclei that are injected into a potient collected at certain sites within its body, undergoing radioactive d...