Photoelectric EffectMedium
Question
A photon of energy 4 eV is incident on a metal surface whose work function is 2eV. The minimum reverse potential to be applied for stopping the emission of the electrons is
Options
A.2V
B.4V
C.6V
D.8V
Solution
From Einstein′s equation of photoelectric effect
hv = φ +
mv2
hv = φ + Ve [V is stoping potential]
4eV = 2eV + Ve
Ve = 2e volt
V × e = 2 × e × 1volt
V(Stoping potential) = 2Volt
hv = φ +
mv2 hv = φ + Ve [V is stoping potential]
4eV = 2eV + Ve
Ve = 2e volt
V × e = 2 × e × 1volt
V(Stoping potential) = 2Volt
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