Nuclear Physics and RadioactivityMedium
Question
In each fission of 92U235 releases 200 MeV, how many fission must occur per second to pruduce power of kW ?
Options
A.1.25 × 1018
B.3.125 × 1013
C.3.2 × 1018
D.1.25 × 1013
Solution
Let n be number of fission per second n × 200 × 106 eV is produced in the one second n × 200 × 106 × 1.6 × 10-19 joule per second
= 1(given)
n =
× 1013 = 3.125 × 1013
= 1(given)n =
× 1013 = 3.125 × 1013 Create a free account to view solution
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