Atomic StructureHard
Question
Activity of a radioactive sample decreases to (1/3)rd of its original value in 9 days its activity will become
Options
A.(1/27)of the original value
B.(1/9)of the original value
C.(1/18)of the original value
D.(1/3)of the original value
Solution
R = R0e-λt
⇒
= e-λ × 3 = e-3λ ......(i)
Let activity in 9 days be. Then
= e-λ × 9 = e-9λe-λ × 3 = (e-3λ)3
=
, from(1)
=
⇒ R′ = 
⇒
= e-λ × 3 = e-3λ ......(i)Let activity in 9 days be. Then
= e-λ × 9 = e-9λe-λ × 3 = (e-3λ)3 =
, from(1)=
⇒ R′ = Create a free account to view solution
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