Atomic StructureHard

Question

A radioactive material decays by simultaneous emission of two particles with respective half lives 1620 and 810 years. The time, in years, after which one-fourth of the material reamins is

Options

A.1080
B.2430
C.3240
D.4860

Solution

= λ1N + λ2N ⇒ loge = - (λ1 + λ2)t
where N0 is intial no. of atom
Here λ1 = and λ2 =
⇒ loge
⇒ 2.303 [-2 × (.3010)]
= - 0.693
⇒   = t = 1080 year.

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