Atomic StructureHard

Question

A radioactive material decays by simultaneous emission of two particles with respective half lives 1620 and 810 years. The time, in years, after which one-fourth of the material reamins is

Options

A.1080
B.2430
C.3240
D.4860

Solution

= λ1N + λ2N ⇒ loge = - (λ1 + λ2)t
where N0 is intial no. of atom
Here λ1 = and λ2 =
⇒ loge
⇒ 2.303 [-2 × (.3010)]
= - 0.693
⇒   = t = 1080 year.

Create a free account to view solution

View Solution Free
Topic: Atomic Structure·Practice all Atomic Structure questions

More Atomic Structure Questions

If the rate of energy emitted from a star is 4.5 × 1035 J/s, then the rate of loss of its mass will be-...X-ray will not show the phenomenon of :...In the following diagram, which particle has highest e/m value?...Calculate power output of reactor, If it takes 30 days to use up 2 kg of fuel, and if each fission gives 185 MeV of usea...The smallest wavelength of Lyman series is 91 nm . The difference between the largest wavelengths of Paschen and Balmer ...