Nuclear Physics and RadioactivityMedium

Question

A radioactive material decays by simultaneous emission of two particles with respective half lives 1620 and 810 years. The time, in years, after which one-fourth of the material reamins is

Options

A.1080
B.2430
C.3240
D.4860

Solution

= λ1N + λ2N ⇒ loge = - (λ1 + λ2)t
where N0 is intial no. of atom
Here λ1 = and λ2 =
⇒ loge
⇒ 2.303 [-2 × (.3010)]
= - 0.693
⇒   = t = 1080 year.

Create a free account to view solution

View Solution Free
Topic: Nuclear Physics and Radioactivity·Practice all Nuclear Physics and Radioactivity questions

More Nuclear Physics and Radioactivity Questions

Mass of an α particle is :-...Activity of radioactive element decreased to one third of original activity R0 in 9 years. After further 9 years, its ac...Which of the following statements is correct?...If the binding energy per nucleon of a nuclide is high then...In an isotope -...