Nuclear Physics and RadioactivityMedium
Question
Consider the following nuclear reaction X200 → A110 + B90 + Energy if the binding energy per nucleon for X, A and B are 7.4 Me V, and B 8.2 Me V respectively the energy released will be :
Options
A.90 MeV
B.110 MeV
C.200 MeV
D.160 MeV
Solution
Energy released = total binding energy energy of A and B less total binding energy of
X = (110 × 8.2 + 90 × 8.2) - (200 × 7.4)( 902 + 738) - 1480
= 160 MeV
X = (110 × 8.2 + 90 × 8.2) - (200 × 7.4)( 902 + 738) - 1480
= 160 MeV
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