NEET | 2017ElectrostaticsEasy

Question

Suppose the charge of a proton and an electron differ slightly. One of them is – e, the other is (e + ∆e). If the net of electrostatic force and gravitational force between two hydrogen atoms placed at a distance d (much greater than atomic size) apart is zero, then ∆e is of the order of [Given mass of hydrogen mh = 1.67 × 10-–27 kg]

Options

A.

10–-23 C

B.

10–-37 C

C.

10-47 C

D.

10-20 C

Solution

K×(∆e)2r2=Gm2r2
∆e=mGm=1.67×10-276.67×10-119×109C
= 1.436 × 10–-37 C

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