MagnetismHard
Question
An electron moving with kinetic energy 6.6 × 10-14 J enters in a magnetic field of 4 × 10-3 T at right angles to it. The radius of its circuclar path will be nearest to :
Options
A.100 cm
B.75 cm
C.25 cm
D.50 cm
Solution
When a charged particle enters a magnetic field, its path becomes circular whoseradius can be found out from the relation.
= Bqv ⇒ r = 
E =
mv2 = 6.6 × 10-14
= 6.6 × 10-14
⇒ m2v2 = 2m = 6.6 × 10-14
mv =
= 50 cm. approx.
= Bqv ⇒ r = E =
mv2 = 6.6 × 10-14 = 6.6 × 10-14⇒ m2v2 = 2m = 6.6 × 10-14
mv =
= 50 cm. approx.
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