MagnetismEasy
Question
A particle of charge -16×10-18 coulomb moving with velocity 10 ms-1 along the x-axis enters a region where a magnetic field of induction B is along the y-axis, and an electric field of magnitude 104 V/m is along the negative z-axis. If the charged particle continues moving along the x-axis, the magnitude of B is
Options
A.103Wb/m2
B.105Wb/m2
C.1016Wb/m2
D.10-3Wb/m2
Solution
.....(1)The solution of this problem can be obtained by resolving the motion along the three coordinate axes namely
ax =
(Ex + vyBz - vzBy)ay =
(Ey + vzBx - vxBz)az =
(Ez + vxBy - vyBz)For the given problem,
Ex = Ey = 0, Vy = vz = 0 and Bx = Bz = 0
Substituting in equation (2), we get
ax = az = 0 and ay = Ey - vxBz
If the particle passes through the region undeflected ay is also zero, then
Ey = vxBz
⇒ Bz =
= 103 Wb/m2Create a free account to view solution
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