NEET | 2017Magnetic field due to currentHard

Question

A 250-Turn rectangular coil of length 2.1 cm and width 1.25 cm carries a current of 85 μA and subjected to magnetic field of strength 0.85 T. Work done for rotating the coil by 180∘ against the torque is:-

Options

A.

4.55 μJ

B.

2.3 μJ

C.

1.15 μJ

D.

9.1 μJ

Solution

Work = MB[cos θ1 - cos θ2]
Work = MB[cos 0 - cos 180o]
W = NiAB[1 - (-1)]
 W ≃9.1 μJ

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