ThermodynamicsHard
Question
When a system is taken from a state i to f along the path iaf (as shown in the figure). Q = 50 cal and W = 20 cal; along path ibf, Q = 36cal.
(i) What is W along path ibf ?
(ii) If W = 13 cal for path fi, what is Q for path fi ?
(iii) Take Eint,i = 10 cal than what is Eint,f ?
(i) What is W along path ibf ?
(ii) If W = 13 cal for path fi, what is Q for path fi ?
(iii) Take Eint,i = 10 cal than what is Eint,f ?
Options
A.30, 20, 40 cal
B.6, -43, 40cal
C.10, -20, 30cal
D.15, 35, 25cal
Solution
For path iaf
Q = 50
W = 20
According ot I law thermodynamics,
dQ = dU + dW
or dU = dQ - dW = 50 - 20 = 30 cal.
(i) For path iaf
Q = 36 cal.
W = ?
dU = 30 cal (since internal energy depemds only on the initial and final position of the system).
∴ W = Q - dU = 36 - 30 = 6 cal.
(ii) W = - 13cal.
dU = - 30 cal.
Q = ?
∴ Q = dU + W = - 43 cal.
Q = 50
W = 20
According ot I law thermodynamics,
dQ = dU + dW
or dU = dQ - dW = 50 - 20 = 30 cal.
(i) For path iaf
Q = 36 cal.
W = ?
dU = 30 cal (since internal energy depemds only on the initial and final position of the system).
∴ W = Q - dU = 36 - 30 = 6 cal.
(ii) W = - 13cal.
dU = - 30 cal.
Q = ?
∴ Q = dU + W = - 43 cal.
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