Momentum and CollisionHard
Question
In the diagram shown all three rods are of equal length L and equal mass M. The system is rotated such that rod B is the axis. What is the moment of inertia of the system ?
Options
A.
B.
ML2
ML2C.
D.
ML2
ML2Solution
Moment of inertia of system
= M.I of A + M.I. of B + M.I. of C
M.I of A =M.T through centre and perpendicular length =
ML2
M.I. of C = M.I of A =ML2
M.I. of B = 0
(moment of mass anout an axis passing through its own position is zero)
∴ M.I =
ML2 + ML2 = 
ML2
= M.I of A + M.I. of B + M.I. of C
M.I of A =M.T through centre and perpendicular length =
ML2M.I. of C = M.I of A =
ML2M.I. of B = 0
(moment of mass anout an axis passing through its own position is zero)
∴ M.I =
ML2 + ML2 = ML2Create a free account to view solution
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