Momentum and CollisionHard

Question

A shell is fired from a cannon with velocity v (m/s) at an angle with the horizontal direction. At the heighest point in its path it explodes into two pieces of equal mass. One of the pieces retraces its path to the cannon and the speed (m/s) of the other pieces immediatly after the explosion is

Options

A.3v cos θ
B.2v cos θ
C. v cos θ
D. v cos θ

Solution

Let v′ be the velocity of second fragment. From conservation of limear momentum,

2m(v cos θ) = mv′ - m(v cos θ)         v′ = 3v cos θ

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