Rotational MotionMedium
Question
The moment of inertia a regular circular disc of mass 0.4 kg and radius 100 cm about an axis per5pendicular to the plant of the disc and passing through its centre is :
Options
A.0.2 kgm2
B.0.02 kgm2
C.0.002 kgm2
D.2 kgm2
Solution
Moment of inertia of a circular disc
=
MR2 = × 0.4 × 1 × 1 = 0.2 kg - m2
=
MR2 = × 0.4 × 1 × 1 = 0.2 kg - m2Create a free account to view solution
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