Momentum and CollisionHard

Question

The U-tube shown has a uniform cross-section. A liquid is filled in the two arms up to heights h1 and h2, and then the liquid is allowed to move. Neglect viscosity and surface tension. When the levels equalize in the two arms, the liquid will

Options

A.be at rest
B.be moving with an acceleration of g
C.be moving with a velocity of (h1 - h2)
D.exert a net force to the right on the tube

Solution

When the levels equalize then the height of the height of the liquid in each arm =
Transferred length of liquid = h1 -
Transferred mass = Aρ
Loss in gravitational potential energy
= mgh = Aρg
Mass of the entire liquid
= (h1 + h2 + h)Aρ
= (h1 + h2 + h)Aρ
If this liquid moves with a velocity v then its KE
(h1 + h2 + h)Aρv2
(h1 - h2)

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