Momentum and CollisionHard

Question

The U-tube shown has a uniform cross-section. A liquid is filled in the two arms up to heights h1 and h2, and then the liquid is allowed to move. Neglect viscosity and surface tension. When the levels equalize in the two arms, the liquid will

Options

A.be at rest
B.be moving with an acceleration of g
C.be moving with a velocity of (h1 - h2)
D.exert a net force to the right on the tube

Solution

When the levels equalize then the height of the height of the liquid in each arm =
Transferred length of liquid = h1 -
Transferred mass = Aρ
Loss in gravitational potential energy
= mgh = Aρg
Mass of the entire liquid
= (h1 + h2 + h)Aρ
= (h1 + h2 + h)Aρ
If this liquid moves with a velocity v then its KE
(h1 + h2 + h)Aρv2
(h1 - h2)

Create a free account to view solution

View Solution Free
Topic: Momentum and Collision·Practice all Momentum and Collision questions

More Momentum and Collision Questions

A liquid flows through a horizontal tube. The velocities of the liquid in the two sections, which have areas of cross-se...Three blocks are initially placed as shown in the figure. Block A has mass m and initial velocity v to the right. Block ...A bead of mass m and diameter d is sliding back and forth with velocity v on a wire between two rigid walls of length L....Two blocks A & B are placed on a smooth surface as shown, horizontal force F is applied on B when A & B are init...Two identical balls are interconnected with a massless and inextensible thread of length L. The system is in gravity fre...