Momentum and CollisionHard
Question
Two balls of same mass are dropped from the same height h, on to the floor. The first ball bounces to a height h/4, after the collision & the second ball to a height h/16. The impulse applied by the first & second ball on a height h/16 The applied by the first & second ball on the floor are I1 and I2 respectively
Options
A.5I1 = 6I2
B.6I1 = 5I2
C.I1 = 2I2
D.2I1 = I2
Solution
For the Ist ball
e12h
For the IInd ball
e22 h Impulse on first ball
= I1 = mv0(1 + e1) =
mv0.
Impulse on second ball
= I2 = mv0(1 + e2) =
mv0.
⇒
⇒ 5I1 = 6I2.
For the IInd ball
= I1 = mv0(1 + e1) =
Impulse on second ball
= I2 = mv0(1 + e2) =
⇒
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