Laws of MotionHard
Question
A parachutist after baling out falls 50 m without friction. When parachute opens, it decelerates at 2 m / s2. He reaches the ground with a speed of 3m/s. AT what height, did he bail out?
Options
A.182m
B.91m
C.111m
D.293m
Solution
v = 
= 14√5
S =
≈ 243m
Initally he has fallen 50m.
∴ Total heigh from where
he baild out = 244 + 50 = 293m
= 14√5S =
≈ 243m Initally he has fallen 50m.
∴ Total heigh from where
he baild out = 244 + 50 = 293m
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