Laws of MotionHard
Question
A parachutist after baling out falls 50 m without friction. When parachute opens, it decelerates at 2 m / s2. He reaches the ground with a speed of 3m/s. AT what height, did he bail out?
Options
A.182m
B.91m
C.111m
D.293m
Solution
v = 
= 14√5
S =
≈ 243m
Initally he has fallen 50m.
∴ Total heigh from where
he baild out = 244 + 50 = 293m
= 14√5S =
≈ 243m Initally he has fallen 50m.
∴ Total heigh from where
he baild out = 244 + 50 = 293m
Create a free account to view solution
View Solution FreeMore Laws of Motion Questions
A tuning fork of known frequency 256 Hz makes 5 beats per second with the vibrating string of a piano. The beat frequenc...Two masses of 10 kg and 20 kg respectively are connected by a massless spring as shown in figure. A force of 200 N acts ...The length of a spring is α when a force of 4 N is applied on it and the length is β when 5 N force is applied...Given mA= 30kg, mB = 10kg, mC = 20 kg . The coefficient of friction between A and B μ1 = 0.3, between B and C μ...A heavy block kept on a frictionless surface and being pulled by two ropes of equal mass m as shown in figure. At t = 0,...