Laws of MotionMedium
Question
A block is sliding down on an inclined plane of slope $\theta$ and at an instant $t = 0$ this block is given an upward momentum so that it starts moving up on the inclined surface with velocity $u$. The distance $(S)$ travelled by the block before its velocity become zero, is $\_\_\_\_$ .
(g = gravitational acceleration)
Options
A.$\frac{u^{2}}{4gsin\theta}$
B.$\frac{2u^{2}}{gcos\theta}$
C.$\frac{u^{2}}{\sqrt{2}gcos\theta}$
D.$\frac{u^{2}}{2gcos\theta}$
Solution
$$\begin{matrix} & a = - gsin\theta \\ & V^{2} = U^{2} + 2as \\ & 0 = u^{2} - 2gsin\theta.s \\ & s = \frac{u^{2}}{2gsin\theta} \end{matrix}$$
NTA Ans- (4)
Ans- (Bonus)
Create a free account to view solution
View Solution FreeMore Laws of Motion Questions
A block is placed on a table. The force of reaction will be :...The ratio of weight of a man in a stationary lift and in a lift accelerating downwards with a uniform acceleration is 3 ...When a lift is descending with an acceleration a, the force exerted by an object of mass m on the lift will be:...A body kept on a smooth inclined plane inclination 1 in x will remain stationary relative to the inclined plane if the p...A block is dragged on smooth plane with the help of a rope which moves with velocity v. The horizontal velocity of the b...