Laws of MotionMedium
Question
A fireman wants to slide down a rope. The rope can bear a tension of 3/4th of the weight of the man. With what minimum acceleration should the fireman slide down :
Options
A.g/3
B.g/6
C.g/4
D.g/2
Solution
mg − 3/4 mg = ma [Newton′s II law for man]
⇒ a = g/4
⇒ a = g/4
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