Math miscellaneousHard
Question
Let f(x) = 
for n ≥ 2 and g(x) = 
(x). Then ∫xn-2g(x)dx equals
for n ≥ 2 and g(x) = (x). Then ∫xn-2g(x)dx equalsOptions
A.
B.
C.
D.
Solution
Here ff(x) = 
ff(x) =
⇒ g(x) = (fofo...of)(x) =
Hence I = ∫xn-2g(x)dx =
∴ I =
ff(x) =
⇒ g(x) = (fofo...of)(x) =
Hence I = ∫xn-2g(x)dx =
∴ I =
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