Math miscellaneousHard

Question

If I_n = dx, n = 0, 1, 2, ... , then

Options

A.I_n = I_{n + 2}

B.

I_{2m + 1} = 10 π

C.

I_2m = 0

D.I_n = I_{n + 1}

Solution

I_n = dx

Now, I_n+2 - I_n =

⇒ I₁ = π, I₂ = 2 cos x dx = 0

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