Math miscellaneousHard
Question
If f(x) = 
xg{x(1 - x)}dx and I2 = 
g{x(1 - x)}dx then the value of 
is
xg{x(1 - x)}dx and I2 = g{x(1 - x)}dx then the value of isOptions
A.2
B.-3
C.-1
D.1
Solution
f(-a) + f(a) = 1
I1 =
xg{x(1 - x)}dx = (1 - x)g{x(1 - x)}dx
2I1 =g{x(1 - x)}dx = I1 ⇒ I2/I1 = 2.
I1 =
xg{x(1 - x)}dx = (1 - x)g{x(1 - x)}dx2I1 =
g{x(1 - x)}dx = I1 ⇒ I2/I1 = 2.Create a free account to view solution
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