CircleMedium
Question
Tangents drawn from the point P(1, 8) to the circle x2 + y2 - 6x - 4y - 11 = 0 touch the circle at the points A and B. The equation of the circumcircle of the triangle PAB is
Options
A.x2 + y2 + 4x - 6y + 19 = 0
B.x2 + y2 - 4x - 10y + 19 = 0
C.x2 + y2 - 2x + 6y - 29 = 0
D.x2 + y2 - 6x - 4y + 19 = 0
Solution
The centre of the circle is C (3, 2).
Since CA and CB are perpendicular to PA and PB, CP is the diameter of the
circumcircle of triangle PAB.
Its equation is
(x - 3) (x - 1) + (y - 2) (y - 8) = 0
or x2 + y2 - 4x - 10y + 19 = 0.
Since CA and CB are perpendicular to PA and PB, CP is the diameter of the
circumcircle of triangle PAB.
Its equation is
(x - 3) (x - 1) + (y - 2) (y - 8) = 0
or x2 + y2 - 4x - 10y + 19 = 0.
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