CircleHard
Question
A particle P starts from the point z0 = 1 + 2i, where i = √-1 . It moves first horizontally away from origin by 5 units and then vertically away from origin by 3 units to reach a point z1. From z1 the particle moves √2 units in the direction of the vector 
and then it moves through an angle 
in anticlockwise direction on a circle with centre at origin, to reach a point z2. The point z2 is given by
and then it moves through an angle in anticlockwise direction on a circle with centre at origin, to reach a point z2. The point z2 is given byOptions
A.6 + 7i
B.- 7 + 6i
C.7 + 6i
D.- 6 + 7i
Solution
z0 ≡ (1 + 2i)
z1 ≡ (6 + 5i)
z2 ≡ (-6 + 7i).
z1 ≡ (6 + 5i)
z2 ≡ (-6 + 7i).
Create a free account to view solution
View Solution FreeMore Circle Questions
The equation of a circle which passes through the three points (3, 0) (1, -6), (4, -1) is -...The intercepts made by the circle x2 + y2 _ 5x _ 13y _ 14 = 0 on the x-axis and y-axis are respectively...The point (0.1, 3.1) with respect to the circle x2 + y2 − 2x − 4y + 3 = 0, is -...The parametric coordinates of any point on the parabola y2 = 4ax can be -...AB is a diameter of a circle. CD is a chord parallel to AB and 2CD = AB. The tangent at B meets the line AC produced at ...