CircleEasy

Question

Equation of line passing through mid point of intercepts made by circle x2 + y2 _ 4x _ 6y = 0 on

co-ordinate axes is

Options

A. 3x + 2y _ 12 = 0
B. 3x + y _ 6 = 0
C. 3x + 4y _ 12 = 0
D. 3x + 2y _ 6 = 0

Solution

given circle x2 + y2 _ 4x _ 6y = 0

it cuts x-axis put y = 0, x = 0, 4

it cuts y-axis put x = 0, y = 0, 6

Hence mid points on x-axis (2, 0)

on y-axis (0, 3)

Equations of line = 1 Þ 3x + 2y _ 6 = 0

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