Trigonometric EquationHard

Question

Locus of centroid of the triangle whose vertices are (a cos t, a sin t), (b sin t, - b cos t) and (1, 0), where t is a parameter, is

Options

A.(3x - 1)2 + (3y)2 = a2 - b2
B.(3x - 1)2 + (3y)2 = a2 + b2
C.(3x + 1)2 + (3y)2 = a2 + b2
D.(3x + 1)2 + (3y)2 = a2 - b2

Solution



Hence, (B) is the correct answer.

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