Trigonometric EquationHard
Question
If 
xf(sin x)dx = A
f(sin x)dx, then A is
xf(sin x)dx = Af(sin x)dx, then A isOptions
A.0
B.π
C.
D.2π
Solution
Let I = 
xf(sin x)dx = (π - x)f(sin x)dx = πf(sin x)dx -I (since f(2a - x) = f(x))
⇒ I = π
f(sinx)dx ⇒ A = π.
xf(sin x)dx = (π - x)f(sin x)dx = πf(sin x)dx -I (since f(2a - x) = f(x))⇒ I = π
f(sinx)dx ⇒ A = π.Create a free account to view solution
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