Trigonometric EquationHard
Question
The equation of a normal to the curve, sin y = x sin 
at x = 0, is :
at x = 0, is :Options
A.2x - √3 y = 0
B.2x + √3 y = 0
C.2y + √3 y = 0
D.2y - √3 x = 0
Solution
∵ sin y = x sin 
at x = 0, y = 0
diff with respect to x
⇒ cos y
+ x cos 
at (0, 0)
⇒ Equation of normal is y - 0 = -
(x - 0)
⇒ 2x + √3 y = 0
at x = 0, y = 0
diff with respect to x
⇒ cos y
+ x cos at (0, 0)
⇒ Equation of normal is y - 0 = -
(x - 0)⇒ 2x + √3 y = 0
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