Trigonometric EquationHard
Question
The equation of a normal to the curve, sin y = x sin 
at x = 0, is :
at x = 0, is :Options
A.2x - √3 y = 0
B.2x + √3 y = 0
C.2y + √3 y = 0
D.2y - √3 x = 0
Solution
∵ sin y = x sin 
at x = 0, y = 0
diff with respect to x
⇒ cos y
+ x cos 
at (0, 0)
⇒ Equation of normal is y - 0 = -
(x - 0)
⇒ 2x + √3 y = 0
at x = 0, y = 0
diff with respect to x
⇒ cos y
+ x cos at (0, 0)
⇒ Equation of normal is y - 0 = -
(x - 0)⇒ 2x + √3 y = 0
Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
dx is equal to...A plane passes through the point A(2, 1, -3). If distance of this plane from origin is maximum, then its equation is...The values of θ satisfying sin 7θ = sin 4θ - sin θ and 0 < θ < are -...sin (π + θ) sin (π - θ) cosec2 θ =...If f(x) = (2x - π)3 + 2x - cosx, then (f-1 (x)) at x = π is equal to -...