ElectrochemistryHard
Question
The molar conductivities ∧oNaOAc and ∧oHCl at infinite dilution in water at 25oC are 91.0 and 426.2 S cm2/mol respectively. To calculate ∧oHOAc, the additional value required is
Options
A.∧oH2O
B.∧oKCl
C.∧oNaOH
D.∧oNaCl
Solution
λoCH3COONa = λoCH3COO- + λoNa+ .......(1)
λoHCl = λoH+ + λoCl-...........(2)
λoNaCl = λoNa + λoCl- ............(3)
λoCH3COOH = (1) + (2) - (3)
λoHCl = λoH+ + λoCl-...........(2)
λoNaCl = λoNa + λoCl- ............(3)
λoCH3COOH = (1) + (2) - (3)
Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
A lead storage battery has initially 200 g of lead and 200 g of PbO2 plus excess H2SO4. Theoretically, how long could th...Mark out the correct statement(s) regarding electrolytic molar conductivity....A solution of sodium sulphate in water is electrolysed using inert electrodes. The products at the cathode and anode are...The following data are obtained in an experiment Solution Conductivity0.01 M HA 3.8 × 10-5Ω-1cm-1100 ml of 0.0...A 0.5 M NaOH solution offers a resistance of 31.6 ohm in a conducivity cell at roomtemperature. What shall be the appori...