ElectrochemistryEasy
Question
The molar conductivities ∧oNaOAc and ∧oHCl at infinite dilution in water at 25oC are 91.0 and 426.2 S cm2/mol respectively. To calculate ∧oHOAc, the additional value required is
Options
A.∧oH2O
B.∧oKCl
C.∧oNaOH
D.∧oNaCl
Solution
λoCH3COONa = λoCH3COO- + λoNa+ .......(1)
λoHCl = λoH+ + λoCl-...........(2)
λoNaCl = λoNa + λoCl- ............(3)
λoCH3COOH = (1) + (2) - (3)
λoHCl = λoH+ + λoCl-...........(2)
λoNaCl = λoNa + λoCl- ............(3)
λoCH3COOH = (1) + (2) - (3)
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