ElectrochemistryHard
Question
For the cell Zn|Zn2+||Cu2+|Cu, if the concentration of both, Zn2+ and Cu2+ ions are doubled, the EMF of the cell
Options
A.doubles
B.reduces to half
C.remains same
D.becomes zero
Solution
$E_{Cell} = E_{Cell}^{o} - \frac{RT}{2F}.\ln\frac{\left\lbrack Zn^{2 +} \right\rbrack}{\left\lbrack Cu^{2 +} \right\rbrack}$
Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
A depolarizer used in dry cell batteries is...Two platinum electrodes were immersed in a solution of CuSO4 and electric current was passed through the solution. After...Acetic acid is titrated with NaOH solution. Which of the following statement is correct for this titration?...The same quantity of electricity is passed through one molar solution of H2SO4 and one molar solution of HCl. The amount...Which of the following facts is not true ?...