ElectrochemistryHard

Question

For the cell Zn|Zn2+||Cu2+|Cu, if the concentration of both, Zn2+ and Cu2+ ions are doubled, the EMF of the cell

Options

A.doubles
B.reduces to half
C.remains same
D.becomes zero

Solution

$E_{Cell} = E_{Cell}^{o} - \frac{RT}{2F}.\ln\frac{\left\lbrack Zn^{2 +} \right\rbrack}{\left\lbrack Cu^{2 +} \right\rbrack}$

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