FrictionEasy
Question
A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 s. then the coefficient of friction is
Options
A.002
B.0.03
C.0.04
D.0.01
Solution
Retardation 
= 0.6 m/sec2
Frictional force = μ mg = ma
∴ μ
= 0.06.
= 0.6 m/sec2Frictional force = μ mg = ma
∴ μ
= 0.06.Create a free account to view solution
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