FrictionEasy
Question
A block A of mass m1 rests on a horizontal table. A light string connected to it passes over a frictionless pulley at the edge of table and from its other end another block B of mass m2 is suspended. The coefficient of kinetic friction between the block and the table is μk. When the block A is sliding on the table, the tension in the string is :-
Options
A.
B.
C.
D.
Solution
For the motion of both blocks
m2g − T = m2a
T − μk m1g = m1a
⇒ a =
For the block of mass ′m2′
m2g − T = m2
T = m2g −
m2g = m2g 
⇒ T =
Hence option (2)
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