In the given figure the value(s) of mass m for which the 100 kg block remains in static equilibrium is
(g = 10 m/s²)

Question

In the given figure the value(s) of mass m for which the 100 kg block remains in static equilibrium is (g = 10 m/s2)

Accepted Answer

There are two possibilities
(i) 100 kg block slides down the incline     100 kg
(ii) 100 kg block slides up the incline     100 kg
case-(i)

we get, 100 g sin 37 − m × (100 g) cos 37 − mg = 0
⇒ m = − 0.3 × 100 × = 36 kg
Case - (ii)

mg = 100 g sin 37 + m g cos 37 × 100
⇒ m = × 0.3
To remain in equilibrium, m ∈ [36, 84] kg
therefore, m can be 37 and 83 kg.

Question