Redox and Equivalent ConceptHard
Question
Reduction of the metal centre in aqueous permanganate ion involves
Options
A.3 electrons in neutral medium
B.5 electrons in neutral medium
C.3 electrons in alkaline medium
D.5 electrons in acidic medium
Solution
In acidic medium
MnO4- + 8H+ + 5e- → Mn2+ + 4H2O
In neutral medium
MnO4- + 2H2O + 3e- → MnO2 + 4OH+
Hence, number of electron loose in acidic and neutral medium 5 and 3 electrons respectively.
MnO4- + 8H+ + 5e- → Mn2+ + 4H2O
In neutral medium
MnO4- + 2H2O + 3e- → MnO2 + 4OH+
Hence, number of electron loose in acidic and neutral medium 5 and 3 electrons respectively.
Create a free account to view solution
View Solution FreeMore Redox and Equivalent Concept Questions
In the reaction, Cl2 + NaOH → NaCl + NaClO3 + H2O, the equivalent weight of H2O is...In which of the following reactions H2O2 acts as a reducing agent? (a) H2O2 + 2H+ + 2e- → 2H2O (b) H2O2 - 2e- U...Preparation of lyphobic sols by chemical method involves...Equivalent weight of a metal is 18.67. When it reacts with chlorine, the mass of metal which will form 162.52 g of metal...An element (X) having equivalent mass E forms an oxide XmOn. The atomic mass of element should be...