JEE Main | 2014Redox and Equivalent ConceptMedium
Question
In which of the following reactions H2O2 acts as a reducing agent?
(a) H2O2 + 2H+ + 2e- → 2H2O
(b) H2O2 - 2e- → O2 + 2H+
(c) H2O2 + 2e- → 2OH-
(d) H2O2 + 2OH- - 2e- → O2 + 2H2O
(a) H2O2 + 2H+ + 2e- → 2H2O
(b) H2O2 - 2e- → O2 + 2H+
(c) H2O2 + 2e- → 2OH-
(d) H2O2 + 2OH- - 2e- → O2 + 2H2O
Options
A.(a), (b)
B.(c), (d)
C.(a), (c)
D.(b), (d)
Solution
The reducing agent oxidises itself.
(a) H2O2-1 + 2H+ + 2e- → 2H2O-2
(b) H2O2-1 - 2e → O20 + 2H+
(c) H2O2-1 + 2e → 2OH-
(d) H2O2-1 + 2e → O20 + H2O
Note : Powers of ′O′ are oxidation number of ′O′ in the compound.
(a) H2O2-1 + 2H+ + 2e- → 2H2O-2
(b) H2O2-1 - 2e → O20 + 2H+
(c) H2O2-1 + 2e → 2OH-
(d) H2O2-1 + 2e → O20 + H2O
Note : Powers of ′O′ are oxidation number of ′O′ in the compound.
Create a free account to view solution
View Solution FreeMore Redox and Equivalent Concept Questions
Oxidation number of Cr in CrO5 is :-...The oxidation state of boron in potassium tetrafluoroborate is...The oxidation state of chromium in the final product formed in the reaction between KI and acidified $K_{2}{Cr}_{2}O_{7}...Which ordering of compounds is according to the decreasing order of the oxidation state of nitrogen?...Which has the maximum number of equivalent per mole of the oxidant?...