Redox and Equivalent ConceptHard
Question
In the reaction, Cl2 + NaOH → NaCl + NaClO3 + H2O, the equivalent weight of H2O is
Options
A.M
B.3M/5
C.6M/5
D.M/2
Solution
$3Cl_{2} + 6NaOH \rightarrow 5NaCl + NaClO_{3} + 3H_{2}O$
The reaction is balanced by the loss and gain of 5 moles of electron per mole of NaClO3 and hence,
$E_{H_{2}O} = \frac{3M}{5}$
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