ElectrochemistryHard
Question
Limiting molar conductivity of NH4OH (i.e., Λom(NH4OH)) is equal to
Options
A.Λom(NH4Cl) + Λom(NaCl) - Λom(NaOH)
B.Λom(NaOH) + Λom(NaCl) - Λom(NH4Cl)
C.Λom(NH4OH) + Λom(NH4Cl) - Λom(HCl)
D.Λom(NH4Cl) + Λom(NaOH) - Λom(NaCl)
Solution
According to KOhlrausch′s law, limiting molar conductivity of NH4OH
Λom(NH4OH) = Λom(NH4Cl) + Λom(NaOH) - Λom(NaCl)
Λom(NH4OH) = Λom(NH4Cl) + Λom(NaOH) - Λom(NaCl)
Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
The oxidation number of Cr in K2Cr2O7 is :...In a cell that utilises the reaction Zn(s) + 2H+(aq) → Zn2+(aq) + H2(g) addition of H2SO4 to cathode compartment, ...Which of the following facts is not true ?...The electrical conductivity of a solution serves as a means of determining the end point in a chemical reaction, involve...Zn | Zn2+ (C1)|| Zn2+ (C2)|Zn. for this cell ᐃG is negative if -...